4(3^2x+1)+17(3x)-7=0

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Solution for 4(3^2x+1)+17(3x)-7=0 equation:



4(3^2x+1)+17(3x)-7=0
We add all the numbers together, and all the variables
173x+4(3^2x+1)-7=0
We multiply parentheses
12x^2+173x+4-7=0
We add all the numbers together, and all the variables
12x^2+173x-3=0
a = 12; b = 173; c = -3;
Δ = b2-4ac
Δ = 1732-4·12·(-3)
Δ = 30073
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(173)-\sqrt{30073}}{2*12}=\frac{-173-\sqrt{30073}}{24} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(173)+\sqrt{30073}}{2*12}=\frac{-173+\sqrt{30073}}{24} $

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